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Question

Calculate the number of electrons present in a pure sample of H2SO4 containing 8 moles of O-atoms?

A
6.022×1025
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B
3.011×1025
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C
12.044×1024
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D
6.022×1026
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Solution

The correct option is A 6.022×1025
From the formula unit of H2SO4, 4 moles of Oatoms are present in 1 mole of H2SO4.

Therefore, 8 moles of Oatomes will be present in
=84 moles of H2SO4

Again, the total number of electrons in one formula unit of (NH4)2SO4
=2+16+8×4=50

So, the total number of electrons in one mole of H2SO4
=50×6.022×1023

Therefore, the total number of electrons in 84 moles of H2SO4
=50×6.022×1023×2=6.022×1025

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