Calculate the number of formula units of $C u S O_{4} .5 H_{2} O$ present in $10^{- 13}$ moles of pure $C u S O_{4} .5 H_{2} O$ .

6.022 \times 10^{10}

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6.022 \times 10^{13}

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6.022 \times 10^{12}

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6.022 \times 10^{9}

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Solution

The correct option is A $6.022 \times 10^{10}$
We know,
1 mole of $C u S O_{4} .5 H_{2} O = 6.022 \times 10^{23}$ formula units of $C u S O_{4} .5 H_{2} O$
So, $10^{- 13}$ moles of pure $C u S O_{4} .5 H_{2} O$
$= 6.022 \times 10^{23} \times 10^{- 13}$ formula units $= 6.022 \times 10^{10}$ formula units of $C u S O_{4} .5 H_{2} O$

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