Question

Calculate the number of g-moles of CaO that could be obtained from 42.54 g of $CaC{O}_3$ and convert the number of g-moles to grams.

Answer 1

Since, on heating it gives the following balanced reaction,
$CaC{O}_3\to CaO+O_2$
Also, g-moles means moles of the species, and moles = $\frac{\text{mass of compound}}{\text{molecular weight of compound}}$
So moles of $CaC{O}_3$ = $\frac{42.54}{100}$ = 0.4254
Hence, moles of CaO = moles of $CaC{O}_3$ = 0.4254 (as per Stoichiometric coefficient of the reaction)
and mass of CaO = moles of CaO X molecular mass of CaO = 56X0.4254 = 23.8224gm