Question

Calculate the number of $KCl{O}_3$ formula units present in 0.5 kilomoles of $KCl{O}_3$.

• A. $9.033\times {10}^{26}$
• B. $12.044\times {10}^{23}$
• C. $3.011\times {10}^{26}$
• D. $6.022\times {10}^{26}$

Answer 1

The correct option is C $3.011\times {10}^{26}$

We know that,
1 mole of $KCl{O}_3$ formula units contain
$=6.022\times {10}^{23}\text{formula units of}KCl{O}_3$
Therefore,
0.5 kilomoles of $KCl{O}_3$ formula units contain
$=0.5\times {10}^3\times 6.022\times {10}^{23}\text{formula units of}KCl{O}_3$
$=3.011\times {10}^{26}\text{formula units of}KCl{O}_3$