Question

Calculate the number of $KCl{O}_3$ formula units present in $0.5$ kilomoles of $KCl{O}_3$.

• A. $15.055\times {10}^{23}$
• B. $12.044\times {10}^{23}$
• C. $15.055\times {10}^{26}$
• D. $12.044\times {10}^{26}$

Answer 1

The correct option is C $15.055\times {10}^{26}$

We know,
$1$ mole of $KCl{O}_3$ formula units
$=6.022\times {10}^{23}\text{formula units of}KCl{O}_3$
Therefore,
$0.5$ kilomoles of $KCl{O}_3$ formula units
$=0.5\times {10}^3\times 6.022\times {10}^{23}\text{formula units of}KCl{O}_3$
$=3.011\times {10}^{26}\text{formula units of}KCl{O}_3$