Calculate the number of magnesium ions present in 0-51 g of magnesium chloride-A- 3-01 - 1023 Mg 2- ionsB- 6-02 - 1021 Mg 2- ionsC- 6-02 - 1023 Mg 2- ionsD- 3-01 - 1021 Mg 2- ions

The correct option is D 3.01 × 1021 Mg2+ ions 1 mole of magnesium chloride, MgCl2 = 24 + (2 × 35.5) = 95 g i.e. 95 g of MgCl2 contains 6.023 × 1023 MgCl2 molec ...

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Standard IX

Chemistry

Molecular Mass

Calculate the...

Question

Calculate the number of magnesium ions present in 0.51 g of magnesium chloride?

6.02 × 10²³ Mg²⁺ ions

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3.01 × 10²¹ Mg²⁺ ions

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3.01 × 10²³ Mg²⁺ ions

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6.02 × 10²¹ Mg²⁺ ions

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Solution

The correct option is B
3.01 × 10²¹ Mg²⁺ ions

1 mole of magnesium chloride, MgCl₂ = 24 + (2 × 35.5) = 95 g
i.e. 95 g of MgCl₂ contains 6.023 × 10²³ MgCl₂ molecules
∴ 0.51 g MgCl₂ contains = (6.023 × 10²³ × 0.51)/95 = 3.01 × 10²¹ MgCl₂ molecules.
Hence, 0.51 g MgCl₂ contains = 3.01 × 10²¹ Mg⁺² ions.

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