Calculate the number of molecules in 11 g of $C O_{2}$ .

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Solution

Gram molecular weight of $C O_{2}$ = 12+2 $\times$ 16 = 44g.
Now, 44g of $C O_{2}$ contains $6.023 \times 10^{23}$ molecules.
$∴$ 11g of $C O_{2}$ contains = $\frac{6.023 \times 10^{23} \times 11}{44}$ = $1.51 \times 10^{23}$ molecules.

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