You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Chemistry

Mole Concept and Avogadro's Number

Calculate the...

Question

Calculate the number of molecules present in 16.8 L gas 'X' at S.T.P.

1.2 \times 10^{23}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.52 \times 10^{23}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3 \times 10^{23}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 \times 10^{23}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $4.52 \times 10^{23}$
The number of molecules in 22.4 L of gas (X) = $6.02 \times 10^{23}$
Thus, the number of molecules in 16.8 L of gas (X) = $\frac{6.02 \times 10^{23} \times 16.8}{22.4}$ = $4.52 \times 10^{23}$

Suggest Corrections

Similar questions

Q. Ratio of

C_{p}

and

C_{v}

of a gas X is 1.4, the number of atom of the gas 'X' present in 11.2 litres of it at NTP will be
(1)

6.02 \times 10^{23}

(2)

1.2 \times 10^{23}

(3)

3.01 \times 10^{23}

(4)

2.01 \times 10^{23}

Q. Calculate the number of moles.
i)

12.046 \times 10^{23}

atoms of Copper
ii)

27.95 g

of Iron
iii)

1.51 \times 10^{23}

molecules of

C O_{2}

Q. 12 g C-12 contains

6.022 \times 10^{23}

atoms of carbon.
(a)

6.022 \times 10^{23}

is known as .............
(b) Calculate the number of carbon atoms present in 48 g C-12.
(c) Which weighs more,

6.022 \times 10^{23}

molecules of

C O_{2}

6.022 \times 10^{23}

molecules of

H_{2} O

One mole of any substance contains $6.022 \times 10^{23}$ atoms/molecules. Number of molecules of $H_{2} S O_{4}$ present in 100 mL of $0.02 M H_{2} S O_{4}$ solution is.............

(a) $12.044 \times 10^{20}$ molecules (b) $6.022 \times 10^{23}$ molecules

500 m l

{N H}_{3}

contains

6.00 \times 10^{23}

molecules at S.T.P. How many molecules are present in

100 m l

{C O}_{2}

at S.T.P?

Join BYJU'S Learning Program

Calculate the number of molecules present in 16.8 L gas 'X' at S.T.P.

The correct option is B 4.52×1023The number of molecules in 22.4 L of gas (X) = 6.02×1023Thus, the number of molecules in 16.8 L of gas (X) = 6.02×1023×16.822.4 = 4.52×1023

The correct option is B $4.52 \times 10^{23}$
The number of molecules in 22.4 L of gas (X) = $6.02 \times 10^{23}$
Thus, the number of molecules in 16.8 L of gas (X) = $\frac{6.02 \times 10^{23} \times 16.8}{22.4}$ = $4.52 \times 10^{23}$