Calculate the number of moles and molecules present in $4.4 g$ of ${C O}_{2}$

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Solution

Weight of $C O_{2}$ in gram per molecules $= (12) + (16 \times 2) = 12 + 32 = 44 g m o l e s$
Now, number of moles of $C O_{2}$ $= n = \frac{w e i g h t}{m o l e c u l a r w e i g h t} = \frac{4.4}{44} = 0.1$
Now,no of molecules $= n \times 6.022 \times 10^{23} = 0.1 \times 6.022 \times 1 0^{23}$
$= 0.622 \times 1 0^{23}$
$= 6.022 \times 1 0^{22}$ molecules

Hence $0.1$ moles and $6.022 \times 1 0^{22}$ molecules are there in $C O_{2}$

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Calculate the number of moles and molecules present in 4.4g of CO2

Weight of CO2 in gram per molecules =(12)+(16×2)=12+32=44g molesNow, number of moles of CO2 =n=weightmolecular weight=4.444=0.1Now,no of molecules=n×6.022×1023=0.1×6.022×1023=0.622×1023=6.022×1022 moleculesHence 0.1 moles and 6.022×1022 molecules are there in CO2

Calculate the number of moles and molecules present in $4.4 g$ of ${C O}_{2}$