Calculate the number of moles in $392$ grams of sulphuric acid.

2

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3

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4

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5

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Solution

The correct option is C $4$
$1 mole of H_{2} S O_{4} = 98 g$
$Thus 98 g of H_{2} S O_{4} = 1 mole of H_{2} S O_{4}$
$\Rightarrow 392 g of H_{2} S O_{4} = 4 moles of H_{2} S O_{4}$

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H_{2} S O_{4}

0.2

Calculate the molality of 1 lt. solution of 93% sulphuric acid .The density of the solution is 1.84 gram per mole

S = 32, H = 1, O = 16

K O H

196

H_{2} S O_{4} = 98

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