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Question

Calculate the number of moles, molecules and total number of atoms present in 5.6cm3 of NH3 at STP.
[Give C=12,O=16,N=14,H=1,He=4]

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Solution

Volume of NH3 at STP= 5.6cm35.6×103dm3
(i) Moles of NH3=VolumeofgasatSTP22.4dm3=5.6×103dm322.4dm3=2.5×104mol
(ii) Number of molecules= moles×Avogadrosnumber
=2.5×104×6.022×1023
=1.5×1020 molecules
(iii) Ammonia has total 4 atom
Number of atoms in 5.6×103dm3
=1.5×1020×4
=6×1020 atoms

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