Question

Calculate the number of moles of electrons present in $11.2L$ of $N_2$.

• A. $14N_A$
• B. $7N_A$
• C. $3.5N_A$
• D. $4.214\times {10}^{23}$

Answer 1

The correct option is B $7N_A$

Number of moles of $N_2$ in $11.2L=\frac{11.2}{22.4}=0.5moles$

Number of atoms in 1 molecule of $N_2=2N$ - atom.

Number of atoms in $0.5mole{N}_2=2\times 0.5=1mol$

Number of electrons per atom of $N=7$

Number of electrons in $1molatoms=7\times N_A$