Calculate the number of moles of helium present in 52g of Helium.

0.050

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13

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1.0

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1.5

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2.0

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Solution

The correct option is B $13$
Molar mass of Helium $= 4 g$
The given mass of Helium $= 52 g$
Thus the number of moles of Helium $= g i v e n m a s s / m o l a r m a s s$
$= 52 / 4$
$= 13$

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