Calculate the number of moles of $N a_{2} S O_{4}$ produced from 2 moles of
$2 N a O H + H_{2} S O_{4} \to N a_{2} S O_{4} + 2 H_{2} O$

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Solution

As per the reaction,
$2 N a O H + H_{2} S O_{4} \to N a_{2} S O_{4} + 2 H_{2} O$
2 mol of $N a O H$ produces 1 mol of $N a_{2} S O_{4}$ .

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N a_{2} S O_{4}

N a O H

2 N a O H + H_{2} S O_{4} \to N a_{2} S O_{4} + 2 H_{2} O

2 N a O H + H_{2} S O_{4} ⟶ N a_{2} S O_{4} + 2 H_{2} O

N a O H + H C l (d i l u t e d) \to N a C l + H_{2} O

2 N a C l + H_{2} S O_{4} \to N a_{2} S O_{4} + 2 H C l

{N a}_{2} {S O}_{4}

N a O H

2 N a O H + H_{2} {S O}_{4} \to {N a}_{2} {S O}_{4} + 2 H_{2} O

74.1 %

N a_{2} S O_{4}

245

93.9 %

N a C l

2 N a C l + H_{2} S O_{4} ⟶ N a_{2} S O_{4} + 2 H C l

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