Calculate the number of moles of NaOH present in 750 ml of 0.4 m. solution. (Molecular weight of NaOH is 40):

0.4

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0.5

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0.3

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0.2

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Solution

The correct option is C 0.3
$\frac{N o . o f m o l e s}{V o l u m e (i n L)} = m o l a r i t y (c o n c e n t r a t i o n)$
$\Rightarrow \frac{n}{v} = m o l a r i t y$
Given, molarity of solution $= 0.4 M$
Volume of solution $= 750 m l = 0.75 l i t r e s$
$∴$ No. of moles(n) $= (0.4) (0.75) = 0.3$

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