Calculate the number of moles of $N a O H$ present in 750ml. of 0.4M solution (Molecular weight of $N a O H$ $=$ $40$ )

0.3

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0.5

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0.9

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0.8

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Solution

The correct option is A $0.3$
Molarity $= \frac{n o . o f m o l e s}{v o l u m e}$

Given, molarity $= 0.4 M$

Volume $= 750 m l = 0.75 L$

No of moles $= M o l a r i t y \times V o l u m e$

$= (0.4) \times (0.75) = \frac{300}{1000}$

$∴$ No. of moles $= 0.3$

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