Question

Calculate the number of moles of $NaOH$ present in 750ml. of 0.4M solution (Molecular weight of $NaOH$ $=$ $40$)

• A. $0.3$
• B. $0.5$
• C. $0.9$
• D. $0.8$

Answer 1

The correct option is A $0.3$

Molarity$=\frac{no.ofmoles}{volume}$

Given, molarity$=0.4M$

Volume$=750ml=0.75L$

No of moles$=Molarity\times Volume$

$=\left(0.4\right)\times \left(0.75\right)=\frac{300}{1000}$

$\therefore$ No. of moles$=0.3$