Calculate the number of moles present in $17$ grams of $A g N O_{3}$ .

0.2

moles

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0.1

moles

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2

moles

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1

moles

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Solution

The correct option is A $0.1$ moles
$17 g A g N O_{3} {g i v e n}$
Molecular weight $= 170 g / m o l$
$M o l e s = \frac{g r a m w e i g h t}{M o l e c u l a r w e i g h t}$
$= \frac{17}{170}$
$= 0.1 m o l e s$

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Calculate the number of moles present in 17 grams of AgNO3.

The correct option is A 0.1 moles17gAgNO3{given}Molecular weight =170g/molMoles=gramweightMolecularweight=17170=0.1moles

Calculate the number of moles present in $17$ grams of $A g N O_{3}$ .

The correct option is A $0.1$ moles
$17 g A g N O_{3} {g i v e n}$
Molecular weight $= 170 g / m o l$
$M o l e s = \frac{g r a m w e i g h t}{M o l e c u l a r w e i g h t}$
$= \frac{17}{170}$
$= 0.1 m o l e s$