Calculate the number of moles present in 17 grams of ${A g N O}_{3}$ .

0.2 moles

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0.1 mole

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2 moles

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1 mole

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Solution

The correct option is B 0.1 mole
Molecular weight of ${A g N O}_{3} = 108 + 14 + 3 \times 16$
$= 122 + 48$
$= 170$

no. of moles $= \frac{w e i g h t g i v e n}{m o l e c u l a r w e i g h t}$
$= \frac{17}{170}$
$= 0.1 m o l e s$

Hence, the correct option is $B$ .

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