Calculate the number of oxalic acid molecules in $100 m L$ of $0.02 N$ oxalic acid solution.

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Solution

$Molarity = \frac{Normality}{Valency factor} = \frac{0.02}{2} = 0.01 M$

No. of molecules in one molar solution $= 6.02 \times 10^{23}$

No. of molecules in $100 m L$ of $0.01 M$ oxalic acid solution

$= \frac{0.01 \times 6.02 \times 10^{23}}{1000} \times 100 = 6.02 \times 10^{20}$ .

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Calculate the number of oxalic acid molecules in 100 mL of 0.02 N oxalic acid solution.

Molarity=NormalityValency factor=0.022=0.01 MNo. of molecules in one molar solution =6.02×1023No. of molecules in 100 mL of 0.01 M oxalic acid solution=0.01×6.02×10231000×100=6.02×1020.

Calculate the number of oxalic acid molecules in $100 m L$ of $0.02 N$ oxalic acid solution.

$Molarity = \frac{Normality}{Valency factor} = \frac{0.02}{2} = 0.01 M$

No. of molecules in one molar solution $= 6.02 \times 10^{23}$

No. of molecules in $100 m L$ of $0.01 M$ oxalic acid solution

$= \frac{0.01 \times 6.02 \times 10^{23}}{1000} \times 100 = 6.02 \times 10^{20}$ .