Calculate the number of oxygen atoms in $0.2 m o l e$ of $N a_{2} C O_{3} \cdot 10 H_{2} O$ .

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Solution

1 mole of $N a_{2} C O_{3} .10 H_{2} O$ contains 13 atoms of oxygen.

0.20 mole will contain $0.20 \times 13 = 2.26$

Hence, no of oxygen atoms = $2.26 \times N_{A}$

$= 15.66 \times 10^{23}$ is the answer.

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