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Question

Calculate the number of oxygen molecules required to combine with 7g of N2 to form N2O3 when 80% of N2 is converted to N2O3.

A
2.3×1023
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B
1.8×1023
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C
1.8×1021
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D
5.4×1021
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Solution

The correct option is B 1.8×1023
Mass of nitrogen given =7 g
Mass of niitrogen reacted =80% of 7 g=5.6g

N2+32 O2N2O3

28 g N2 reacts with 48 g O2 to give N2O3, so
5.6 g of N2 will react with 4828×5.6 g of O2

16g of O2 has 6.022×1023 molecules,
(4828×5.6) g of O2 has

6.022×102316×4828×5.6=3.6×1023 molecules

Hence the answer is B

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