Question

Calculate the number of particles in 46 g of sodium atoms.

Answer 1

We know that,

One mole of Sodium= $6.022\times {10}^{23}\mathrm{particles}$

Number of moles =$\frac{\mathrm{Given}\mathrm{mass}}{\mathrm{Molar}\mathrm{mass}}$

Number of moles of Sodium =$\frac{46}{23}$= 2 moles

So, 2 moles of Sodium atom contains $6.022\times {10}^{23}\times 2$ =$12.044\times {10}^{23}$particles.