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Ionic Compounds Chemical Formula

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Question

Calculate the number of polyatomic ions from the compounds given below :
$N H_{4}^{+}, N a^{+}, C l^{-}, H^{+}, P O_{4}^{3 -}, N O_{3}^{-}, O H^{-}, O_{2}^{-}$

A

2

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B

3

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C

4

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D

5

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Solution

The correct option is B $4$
$N H_{4}^{+}, P O_{4}^{-}, N O_{3}^{-}, O H^{-}$ are polyatomic ions.

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Similar questions

Identify the monoatomic and polyatomic ions from the following equation-
$P b (N O_{3})_{2}$ + $K_{2} S O_{4}$ $\to$ $2 K N O_{3}$ + $P b S O_{4}$

Q. Calculate the number of polyatomic ions which will use brackets when they are used.

O H

N H_{4}

C O_{3}

O C l

O H

P O_{4}

S O_{4}

$({N H}_{4})^{+}$ , $({S O}_{4})^{2 -}$ are examples of _________________.

Q. Which of the above represents the formula for the most common compound of A and B, where A and B represent given pairs of elements or polyatomic ions as indicated below?
A)

N H_{4}^{+}

C l

Q. Complete the table.

S. No	Formula of the ion	Polyatomic ion	Name of the ion
1.	$C O_{3}^{2 -}$	tetra-atomic	Carbonate ion
2.	$M n O_{4}^{-}$
3.	$H S O_{4}^{-}$
4.	$O_{2}^{2 -}$
5.	$C l O^{-}$

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