Calculate the number of polyatomic ions which will use brackets when they are used.
One $O H$ , two $N H_{4}$ , three $C O_{3}$ ,one $O C l$ , two $O H$ , one $P O_{4}$ , one $S O_{4}$

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Solution

The correct option is A $3$
More than one poly atomic ions are written in brackets so there are three polyatomic ions which are more than one.

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Similar questions

N H_{4}^{+}, N a^{+}, C l^{-}, H^{+}, P O_{4}^{3 -}, N O_{3}^{-}, O H^{-}, O_{2}^{-}

Which of these is a polyatomic ion?

${S O}_{4}^{- 2}$ , ${N O}_{3}^{- 1}$ , ${C O}_{3}^{- 2}$

A l (O H)_{3}

Z n (O H)_{2}

8.5 \times 10^{- 23}

1.8 \times 10^{- 14}

A l^{3 +}

Z n^{2 +}

N H_{4} O H

S O_{4}

C O_{3}

O H

C r_{2} O_{7}

Identify the monoatomic and polyatomic ions from the following equation-
$P b (N O_{3})_{2}$ + $K_{2} S O_{4}$ $\to$ $2 K N O_{3}$ + $P b S O_{4}$

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