Calculate the number of unpaired electrons in Cu2+ and Cr3+ and compare their magnetic nature.

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Solution

$C u - 29 h a s c o n f i g u r a t i o n a s 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{1} 3 d^{10} T h e n u m b e r o f u n p a r i e d e l e c t r o n i n c o p p e r i s 1 S o i t s m a g n e t i c m o m e n t i s \sqrt{n (n + 2)} B M w h e r e n i s n u m b e r o f u n p a i r e d e l e c t r o n M a g n e t i c m o m e n t = \sqrt{n (n + 2)} B M = \sqrt{1 (1 + 2)} B M = \sqrt{3} B M C r - 24 h a s c o n f i g u r a t i o n a s 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{1} 3 d^{5} T h e n u m b e r o f u n p a r i e d e l e c t r o n i n c h r o m i u m i s 6 S o i t s m a g n e t i c m o m e n t i s \sqrt{n (n + 2)} B M w h e r e n i s n u m b e r o f u n p a i r e d e l e c t r o n M a g n e t i c m o m e n t = \sqrt{n (n + 2)} B M = \sqrt{6 (6 + 2)} B M = \sqrt{48} B M$

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Q. In the ground state of cobalt atom (Z=27), number of unpaired electrons and the magnetic nature of cobalt are respectively.

Calculate the number of unpaired electrons in the following gaseous ions: Mn³⁺, Cr³⁺, V³⁺ and Ti³⁺. Which one of these is the most stable in aqueous solution?

Q. Find the number of unpaired electrons in

{C r}^{3 +}

ion.

Q. The number of unpaired electrons in

C r^{3 +}

ion is:

Q. Statement 1: The number of unpaired electrons in the following ions:

M n^{2 +}, C r^{3 +}, V^{3 +}

and

T i^{3 +}

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has a magnetic moment

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