Calculate the number of unpaired electrons in the following gaseous ions- Mn 3- Cr 3- V 3- and Ti 3- Which one of these is the most stable in aqueous solution-

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Abundance and Isotopes

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Calculate the number of unpaired electrons in the following gaseous ions: Mn³⁺, Cr³⁺, V³⁺ and Ti³⁺. Which one of these is the most stable in aqueous solution?

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M n^{3 +}, C r^{3 +}, V^{3 +}

T i^{3 +}

^{3 +}

Which one of the following ions is the most stable in aqueous solution?
(Atomic number. Ti = 22, V = 23, Cr = 24, Mn = 25)

M n^{3 +}

C r^{3 +}

V^{3 +}

M n^{2 +}, C r^{3 +}, V^{3 +}

T i^{3 +}

V^{3 +}

(8)^{\frac{1}{2}} B M

3 d

T i^{4 +}, V^{2 +}, M n^{3 +}, C r^{3 +}

T i = 22, V = 23, M n = 25, C r = 24)

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	Gaseous ions	Number of unpaired electrons
(i)		4
(ii)		3
(iii)		2
(vi)		1