Calculate the number of waves made by a Bohr electron in the 2nd excited state of hydrogen atom?
A
1
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B
2
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C
3
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D
4
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Solution
The correct option is C3 When electron waves are in phase, 2πr=nλ
Where, n represents the number of waves made by the electron as well as the orbit number.
Since, n=3 for 2nd excited state. ∴number of waves made by electron=3