Calculate the number of ways in which 10 different students can be divided into two groups under two different teachers containing 6 and 4 students respectively.

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none of these

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Solution

The correct option is C
Soln:

No. of ways = $\frac{10!}{(6! 4!)} \times 2!$

Here we multiply by $2!$ Because the groups are distinct.

Hence option (c)

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Calculate the number of ways in which 10 different students can be divided into two groups under two different teachers containing 6 and 4 students respectively.

The correct option is C Soln: No. of ways =10!(6!4!)×2! Here we multiply by 2! Because the groups are distinct. Hence option (c)

The correct option is C
Soln:

No. of ways = $\frac{10!}{(6! 4!)} \times 2!$

Here we multiply by $2!$ Because the groups are distinct.

Hence option (c)