Question

Calculate the number of ways in which 10 different students can be divided into two groups under two different teachers containing 6 and 4 students respectively.

• A.
• B. ¹⁰C₆*¹⁰C₄
• C.
• D.

Answer 1

The correct option is C

No. of ways =$\frac{10!}{(6!4!)}\times 2!$

Here we multiply by$2!$ Because the groups are distinct.