Calculate the number of ways in which 10 different students can be divided into two groups containing 6 and 4 students respectively.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

¹⁰C₆*¹⁰C₄

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

none of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
Soln:

No. of ways = $\frac{10!}{(6! 4!)}$

Hence option (c)

2nd method:- Select any six then other four will be automatically selected. i.e $^{10} C_{6} = \frac{10!}{(6! 4!)}$

Suggest Corrections

Similar questions

Q. Calculate the number of ways in which 10 different students can be divided into two groups containing 6 and 4 students respectively.

Calculate the number of ways in which 10 different students can be divided into two groups under two different teachers containing 6 and 4 students respectively.

Q. Number of ways in which

10

different things can be divided into two groups containing

6

and

4

things respectively is ?

Q. The number of ways in which

10

students can be divided into three teams, one containing

4

and others

3

each, is

Q. Find the number of ways in which 12 students may be equally divided into three groups.

Join BYJU'S Learning Program

Calculate the number of ways in which 10 different students can be divided into two groups containing 6 and 4 students respectively.

The correct option is C Soln: No. of ways = 10!(6!4!) Hence option (c) 2nd method:- Select any six then other four will be automatically selected. i.e 10C6=10!(6!4!)

The correct option is C
Soln:

No. of ways = $\frac{10!}{(6! 4!)}$

Hence option (c)

2nd method:- Select any six then other four will be automatically selected. i.e $^{10} C_{6} = \frac{10!}{(6! 4!)}$