Calculate the number of ways in which 10 different students can be divided into two groups containing 6 and 4 students respectively.

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Solution

The correct option is C
No. of ways = $\frac{10!}{(6! 4!)}$

2nd method:- Select any six then other four will be automatically selected. i.e $^{10} C_{6} = \frac{10!}{(6! 4!)}$

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Calculate the number of ways in which 10 different students can be divided into two groups containing 6 and 4 students respectively.

The correct option is C No. of ways = 10!(6!4!) 2nd method:- Select any six then other four will be automatically selected. i.e 10C6=10!(6!4!)

The correct option is C
No. of ways = $\frac{10!}{(6! 4!)}$

2nd method:- Select any six then other four will be automatically selected. i.e $^{10} C_{6} = \frac{10!}{(6! 4!)}$