Question

Calculate the $\%$ of carbon present in ethyl alcohol with a Molecular Formula $C_2{H}_{5}OH$.

Answer 1

Percentage composition=$\frac{massofelement\times 100}{molarmassofcompound}$

Mass of carbon =$12$

Mass of hydrogen(H)=$1$

Mass of oxygen=$16$

Molar mass of compound =$\left[\right(12\times 2)+5+16+1]$

$[46+5+16+1]=46$

% composition of carbon=$\left[\frac{24\times 100}{46}\right]=52$

percentage of hydrogen=$\left[\frac{6\times 100}{46}\right]=13.04$

percentage of oxygen=$\left[\frac{16\times 100}{46}\right]=34.78$