Calculate the % of:
oxygen in calcium hydroxide

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Solution

Formula to calculate the % of an element in a compound:
$% c o m p o s i t i o n o f a n e l e m e n t = \frac{N u m b e r o f a t o m s o f t h e e l e m e n t \times A t o m i c w e i g h t o f t h e e l e m e n t}{M o l e c u l a r w e i g h t o f t h e c o m p o u n d} \times 100$
Step-1: Calculate the molecular weight of Calcium hydroxide [Ca(OH)₂]
Atomic weight of Calcium (Ca)= 40 u
Atomic weight of Hydrogen (H)= 1 u
Atomic weight of Oxygen (O)= 16 u
Molecular weight of Calcium hydroxide [Ca(OH)₂] =Atomic weight of Calcium (Ca)+ 2[Atomic weight of Hydrogen (H)]+ 2[Atomic weight of Oxygen (O)]
Molecular weight of Calcium hydroxide [Ca(OH)₂] =40+ 2(1) +2(16)
Molecular weight of Calcium hydroxide [Ca(OH)₂] =74 u
Step-2: Calculate the % of Oxygen in Calcium hydroxide
Number of atoms of Oxygen in Calcium hydroxide= 2
Amount of Oxygen in Calcium hydroxide= 32 u
Molecular weight of Calcium hydroxide= 74 u
Substituting the values in the given formula above
$% c o m p o s i t i o n o f O x y g e n = \frac{2 \times 16}{74} \times 100 = 43.24 %$
Therefore, the % of oxygen in Calcium hydroxide is 43.24 %

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