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Relative Lowering of Vapour Pressure

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Question

Calculate the osmotic pressure at $27^{\circ} C$ of an aqueous solution, containing 4.4 g of glucose per 100 ml solution.

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Solution

$π$ V= $\frac{w}{M}$ RT

V= $\frac{100}{1000} = 0.1$ litre

w = 4.4 g

T = 27 + 273 = 300 K

M = 180
$π$ = ?

R = 0.0821 l-atm $K^{- 1} m o l^{- 1}$

$∴ π = \frac{w R T}{V M}$

= $\frac{4.4 \times 0.0821 \times 300}{0.1 \times 180}$

$π$ = 6 atm

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