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Osmotic Pressure

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Question

Calculate the osmotic pressure of $5 %$ solution of glucose at $25^{o} C$ . (Molecular weight of Glucose $= 180$ and $R = 0.0821$ liter atm $K^{- 1} m o l^{- 1}$ )

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Solution

According to Question $V = 100 m l = 0.1 l i t e r$
$π = \frac{W_{B}}{M_{B}} \times \frac{R T}{V}$
$= \frac{5}{180} \times \frac{0.0821 \times 298}{0.1}$
$= 0.679$

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