Question

Calculate the osmotic pressure of a solution at $566K$ if the osmotic pressure of a solution at ${10}^{\circ }C$ is $5atm$.

• A. $2.5atm$
• B. $5atm$
• C. $10atm$
• D. $0.5atm$

Answer 1

The correct option is C $10atm$

Osmotic pressure $\left(\pi \right)$ is given by
$\pi =CRT$
where
$C\text{is the concentration (molarity)}R\text{is ideal gas constant}T\text{is temperature}$
Condition 1:
When temperature is ${10}^{\circ }C=283K$
${\pi }_1=C\times R\times 283..eq\left(i\right)$

Condition 2:
When temperature is $566K$
${\pi }_2=C\times R\times 566..eq\left(ii\right)$
Dividing both the equations:

$\frac{{\pi }_1}{{\pi }_2}=\frac{C\times R\times 283}{C\times R\times 566}\frac{5}{{\pi }_2}=\frac{283}{566}{\pi }_2=10atm$