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Question

Calculate the osmotic pressure of the solution obtained by mixing 1 L of 7.5% solution of a substance A (molecular weight =75) and 2 L of 5% solution of a substance B(molecular weight =60) at 180oC.

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Solution

A =7.5%=75gL1
B=5%=50gL1=100g(2L)1
Total volume =3 L=3000 mL
MwA=W2×1000Mw2×Volumeofsolution=75×100075×3000=0.33
MwB=100×100060×3000=0.555
π=(MwA+MwB)RT
=(0.33+0.555)×0.082×453
=0.888×0.082×453=33.05atm

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