Calculate the oxidation no. of sulphur in H2S––4O6.
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Solution
Let X be the oxidation state of S in H2S4O6. 2(+1)+4X+6(2−)=0 X=+52 Hence, the oxidation state of S in H2S4O6 is +5/2. But oxidation number cannot be fractional. Terminal S atoms have +5 oxidation number and middle S atoms have 0 oxidation number.