Calculate the oxidation number of each sulphur atom in ${N a}_{2} S_{2} O_{3}$ .

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Solution

Let the oxidation number of sulphur atom is $x$ .
$N a_{2} {x S}_{2} O_{3}$
$2 \times (+ 1) + 2 x + (- 2) \times 3 = 0$
$2 + 2 x - 6 = 0$
$2 x - 4 = 0$
$2 x = 4$
$x = + 2 (wrong)$
By conventional method, we can't find the oxidation number of each sulphur atom.
It will be well explained by structure. One sulphur has $+ 6$ O.S, whereas another has $- 2$ .

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