Calculate the oxidation number of $M n$ in the product obtained on an alkaline oxidative fusion of $M n O_{2}$ .
(Give the absolute value of an answer)

Open in App

Solution

The balanced chemical equation for the alkaline oxidative fusion of $M n O_{2}$ is as given below:

$2 M n O_{2} + 4 K O H + O_{2} \to 2 K_{2} M n O_{4} + 2 H_{2} O$

Let $x$ be the oxidation number of Mn in $K_{2} M n O_{4}$ .

Hence, $2 (+ 1) + x + 4 (- 2) = 0$ (for a neutral compound)

or, $x = + 6$

Hence, the oxidation number of $M n$ in the product obtained on alkaline oxidative fusion of $M n O_{2}$ is $+ 6$ .

Suggest Corrections

Similar questions

M n

M n_{2} O_{7}

M n O_{2}

M g_{2} {P - -}_{2} O_{7}

M n

M n O_{2}

C N^{-}

Join BYJU'S Learning Program