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Question

Calculate the oxidation number of phosphorus in the following species.

A) HPO23

B) PO34

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Solution

A)
Let the oxidation number of phosphorous be x in HPO23
+1+x+(2)×3=2
+1+x6=2
x5=2
x=+3
Hence, oxidation number of phosphorus in HPO23 is +3.

B)
Let the oxidation number of phosphorous be x in PO34
x+(2)×4=3
x8=3
x=+5

Thus, oxidation number of phosphorus in PO34 is +5.

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