Question

Calculate the oxidation number sulphur in (i) Na₂S₂O₃(ii) S₂O₄^2-

Answer 1

Dear User,
Oxidation number of S in
(i) Na₂S₂O₃ :
2(+1) + 2x + 3(-2) = 0
2 + 2x -6 = 0
2x - 4 = 0
2x = 4
or, x = 2
Therefore oxidation number of S is +2

(ii) S₂O₄^2-
2x + 4(-2) = -2
2x - 8 = -2
2x = 6
x=3
Therefore, oxidation number of S is +3.