Calculate the partial pressure of carbon monoxide from the following
$C a C O_{3} (s)$ $Δ \to C a O (s) + C O_{2} ↑; K_{p} = 8 \times 10^{- 2}$
$C O_{2} (g) + C (s) \to 2 C O (g); K_{p} = 2$

0.2

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0.4

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1.6

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4

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Solution

The correct option is B $0.4$
$K p = \frac{Partial pressure of reactant}{Partial pressure of product}$

Given:- $C a C O_{3} (s) \to C a O (s) + C O_{2} (g)$ ;Kp = $8 \times 10^{- 2}$

From the above reaction- Kp = $P_{C O_{2}} = 8 \times 10^{- 2}$ .....(1)
$C (s) + C O_{2} (g) \to 2 C O (g)$ ;Kp=2

From the above reaction- K p = $\frac{{P_{C O}}^{2}}{(P_{C O_{2}})}$

the partial pressure is 0.4

hence B is correct answer

Suggest Corrections

Similar questions

C a C O_{3} (s) Δ ⟶ C a O (s) + C O_{2} (g); K_{p} = 8 \times 10^{- 2} C O_{2} (g) + C (s) \to 2 C O (g) K_{p} = 2

C a C O_{3 (s)} Δ ⟶ {C a O}_{(s)} + {C O}_{2} ↑; K_{p} = 8 \times 10^{- 2}

C O_{2 (g)} C_{(s)} \to {2 C O}_{(g)}

K_{p} = 2

C a {C O}_{3} (s) Δ \to C a O (s) + {C O}_{2} ↑; K_{p} = 8 \times 10^{- 2}

{C O}_{2} (s) + C (s) ⟶ 2 C O (s); K_{p} = 2

C (s) + C O_{2} (g) ⇌ 2 C O (g)

C O_{2}

K_{p}

C (s) + C O_{2} (g) ⇌ 2 C O (g)

12 a t m

50

{C O}_{2}

K_{p}

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