Question

Calculate the Pearson's Coefficient of correlation between X and Y.

X	35	34	40	43	56	20	38
Y	32	30	31	32	53	20	33

• A. 0.12
• B. 0.93
• C. 0.71
• D. 0.56

Answer 1

The correct option is B 0.93

$X35344043562038\_\_\_\_\_\_\_\_\_\_\sum X=266$ $Y32303132532033\_\_\_\_\_\_\_\_\_\_\sum Y=231$ $x-\overline{x}-3-4020518-1800\_\_\_\_\_\_\_\_\_\_\_\sum (x-\overline{x)}=0$ $y-\overline{y}-1-3-2-120-1300\_\_\_\_\_\_\_\_\_\_\_\_\sum (y-\overline{y})=0$ $XY0312-4-5360234000\_\_\_\_600$

$X^{2}09160425324324000\_\_\_\_702$ $Y^{2}19414001690\_\_\_\_\_\_\_\_\_\_\sum Y^2=584$

Therefore, $\overline{x}=\frac{266}{7}=38$ $\overline{y}=\frac{231}{7}=33$

$r=\frac{\sum XY}{\sum X^2\sum Y^2}=\frac{600}{\sqrt{702\ast 584}}=\frac{600}{640\ast 287}=\mathrm{0.93.}$

Therefore, $r=\mathrm{0.93.}$