Calculate the percent composition of carbon in $C_{6} H_{12} O_{6}$ :

50

No worries! We‘ve got your back. Try BYJU‘S free classes today!

40

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

35.3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

22.1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $40$
Molar mass of compound $: 6 (12.0) + 12 (1.01) + 6 (16.0) = 180 g / m o l$
Mass due to carbon $= 6 (12.0) = 72.06 g / m o l$
composition of $C = 72 / 180 \times 100 = 40$

Suggest Corrections

Similar questions

C_{6} H_{12} O_{6}

C_{6} H_{12} O_{6}

C O_{2}

%

(N a_{2} C O_{3})

Join BYJU'S Learning Program