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Salt of Weak Acid and Strong Base

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Question

Calculate the percent hydrolysis in $0.006 M$ solution of $K C N$ .

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Solution

Strong base is $N a O H$ and weak acid is $H O C N$
Degree of hydrolysis for weak acid and strong base is given by $h = \sqrt{\frac{K_{w}}{K_{a} . C}}$
$K_{w} = 10^{- 14}, K_{a} = 3.3 \times 10^{- 4}, C = 0.003 M$
$h = \sqrt{\frac{10^{- 14}}{3.3 \times 10^{- 4} (0.003)}} = \sqrt{10^{- 8}} = 0.0001 = 0.0001 \times 100 % = 0.01 %$

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