Calculate the percentage by weight of: (a) $C$ in $C O_{2}$ , (b) $N a$ in $N a C O_{3}$ , (c) $A l$ in aluminium nitride.
[ $C = 12, O = 16, H = 1, N a = 23, A l = 27, N = 14$ ]

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Solution

(a) Molar mass of $C = 12 g$
Molecular mass of $C O_{2} = 44 g$
Therefore,
Percentage by weight of $C$ in $C O_{2} = \frac{12}{44} \times 100 = 27.27 %$
(b) Molar mass of $N a = 23 g$
Molecular mass of ${N a}_{2} C O_{3} = 106 g$
Therefore,
Percentage by weight of $N a$ in ${N a}_{2} C O_{3} = \frac{23}{106} \times 100 = 21.27 %$
(c) Molar mass of $A l = 27 g$
Molecular mass of Aluminium nitride $(A l N) = 41 g$
Therefore,
Percentage by weight of $A l$ in $A l N = \frac{27}{41} \times 100 = 65.85 %$

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