Question

calculate the percentage composition of all the elements present in ammonium sulphate

Answer 1

$$\begin{gathered} \text{Molecular mass ofAmmonium sulphate =}{\left({\mathrm{NH}}_4\right)}_2{\mathrm{SO}}_4 \\ =14\mathrm{X}2+8\mathrm{X}1+32+4\mathrm{X}16=132 \\ =132 \\ \%\mathrm{of}\mathrm{nitrogen}=\frac{28}{132}\times 100=21.21\% \\ \%\mathrm{of}\mathrm{hydrogen}=\frac{8}{60}\times 100=6.06\% \\ \%\mathrm{of}\mathrm{sulphur}=\frac{32}{132}\times 100=24,24\% \\ \%\mathrm{of}\mathrm{oxygen}=\frac{64}{60}\times 100=48.48\% \\ \mathrm{Regards} \end{gathered}$$