Question

Calculate the percentage composition of each element in Potassium chlorate, $KCl{O}_3$

Answer 1

Molar Mass of $KCl{O}_3$
= $39+35.5+48g$
= $122.5g$ .

So , percentage of Potassium ( K )
= $\frac{39}{122.5}$ $\times 100$
= 31.83 %

Now , percentage of Chlorine ( Cl )
= $35.5/122.5\times 100$
= 28.97 %

So, finally, percentage of Oxygen ( O )
= $48/122.5\times 100$
= 39.18 %