Calculate the percentage composition of nitrogen in $N H_{4} N O_{3} .$

20 %

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34%

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25%

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35%

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Solution

The correct option is D
35%

Molecular weight of NH₄NO₃= 14 + 4 + 14 +48 = 80 amu.

Also, weight of nitrogen in $N H_{4} N O_{3} = \frac{28}{80} \times 100$

= 35%

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Similar questions

Calculate the percentage of Nitrogen in the fertilizer, Ammonium Nitrate $N H_{4} N O_{3}$

[H = 1, N = 14, O = 16]

H_{2} N C O N H_{2}

X	Below 5	5−10	10−15	15−20	20−25	25−30	30−35	35−40	Above 40
Y	20	24	32	28	20	16	34	10	8

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